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(3x+2)(2x+1)=(6x-4)(x-1)
We move all terms to the left:
(3x+2)(2x+1)-((6x-4)(x-1))=0
We multiply parentheses ..
(+6x^2+3x+4x+2)-((6x-4)(x-1))=0
We calculate terms in parentheses: -((6x-4)(x-1)), so:We get rid of parentheses
(6x-4)(x-1)
We multiply parentheses ..
(+6x^2-6x-4x+4)
We get rid of parentheses
6x^2-6x-4x+4
We add all the numbers together, and all the variables
6x^2-10x+4
Back to the equation:
-(6x^2-10x+4)
6x^2-6x^2+3x+4x+10x+2-4=0
We add all the numbers together, and all the variables
17x-2=0
We move all terms containing x to the left, all other terms to the right
17x=2
x=2/17
x=2/17
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