(3x+2)(2x+1)=6x2+2

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Solution for (3x+2)(2x+1)=6x2+2 equation: 



(3x+2)(2x+1)=6x^2+2

We move all terms to the left:

(3x+2)(2x+1)-(6x^2+2)=0

We get rid of parentheses

-6x^2+(3x+2)(2x+1)-2=0

We multiply parentheses ..

-6x^2+(+6x^2+3x+4x+2)-2=0

We get rid of parentheses

-6x^2+6x^2+3x+4x+2-2=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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