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(3x+2)(2x+23)=180
We move all terms to the left:
(3x+2)(2x+23)-(180)=0
We multiply parentheses ..
(+6x^2+69x+4x+46)-180=0
We get rid of parentheses
6x^2+69x+4x+46-180=0
We add all the numbers together, and all the variables
6x^2+73x-134=0
a = 6; b = 73; c = -134;
Δ = b2-4ac
Δ = 732-4·6·(-134)
Δ = 8545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-\sqrt{8545}}{2*6}=\frac{-73-\sqrt{8545}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+\sqrt{8545}}{2*6}=\frac{-73+\sqrt{8545}}{12} $
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