(3x+2)(2x-3)=-3/2

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Solution for (3x+2)(2x-3)=-3/2 equation: 



(3x+2)(2x-3)=-3/2

We move all terms to the left:

(3x+2)(2x-3)-(-3/2)=0

We get rid of parentheses

(3x+2)(2x-3)+3/2=0

We multiply parentheses ..

(+6x^2-9x+4x-6)+3/2=0

We multiply all the terms by the denominator


((+6x^2-9x+4x-6))*2+3=0

We move all terms containing x to the left, all other terms to the right

((+6x^2-9x+4x-6))*2=-3

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