If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(3x+2)(2x-7)=140
We move all terms to the left:
(3x+2)(2x-7)-(140)=0
We multiply parentheses ..
(+6x^2-21x+4x-14)-140=0
We get rid of parentheses
6x^2-21x+4x-14-140=0
We add all the numbers together, and all the variables
6x^2-17x-154=0
a = 6; b = -17; c = -154;
Δ = b2-4ac
Δ = -172-4·6·(-154)
Δ = 3985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{3985}}{2*6}=\frac{17-\sqrt{3985}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{3985}}{2*6}=\frac{17+\sqrt{3985}}{12} $
| 93=4x+7x-6 | | 6+(w−10)=5 | | 6x-2+2x=94 | | -1/4x^2+7x+1=0 | | .25(x-13)=7 | | 8=f-5/7 | | 20=5+z+7+z | | x2=25/49 | | 2+18/2x=5 | | 60|2s+5|=64 | | -1/2x^2+20x+2=0 | | x+3/6=3/9 | | 2x/2+4=8 | | (x-3)^2=-64 | | 4x+3+x=2+5x+1 | | -1/2x^2+2x+2=0 | | 128+c=3,012 | | 15=6+6+z | | |n-10|=4 | | 2x-3/5x+1=0 | | -1/2x^2+6x+2=0 | | 3x+15=18. | | 2x+4+4x-2=3x+8+3x+4 | | m=-3(2,-1) | | 7^5x-5=1/49 | | 2(4x+12)=-4(-2x-3) | | 0=-16t^2+300t+6 | | 4x^2+24x+6=0 | | (3x-6)/(2x^2-18)=0 | | 11x2-34x+3=0 | | 25x-18=30x-10 | | 5/2s=-15 |