(3x+2)(3x-2)=9x(x-8)

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Solution for (3x+2)(3x-2)=9x(x-8) equation: 



(3x+2)(3x-2)=9x(x-8)

We move all terms to the left:

(3x+2)(3x-2)-(9x(x-8))=0

We use the square of the difference formula

9x^2-(9x(x-8))-4=0



We calculate terms in parentheses: -(9x(x-8)), so:

9x(x-8)

We multiply parentheses

9x^2-72x

Back to the equation:

-(9x^2-72x)



We get rid of parentheses

9x^2-9x^2+72x-4=0

We add all the numbers together, and all the variables

72x-4=0

We move all terms containing x to the left, all other terms to the right

72x=4

x=4/72

x=1/18

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