(3x+2)(x+1)=

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Solution for (3x+2)(x+1)= equation:


Simplifying
(3x + 2)(x + 1) = 0

Reorder the terms:
(2 + 3x)(x + 1) = 0

Reorder the terms:
(2 + 3x)(1 + x) = 0

Multiply (2 + 3x) * (1 + x)
(2(1 + x) + 3x * (1 + x)) = 0
((1 * 2 + x * 2) + 3x * (1 + x)) = 0
((2 + 2x) + 3x * (1 + x)) = 0
(2 + 2x + (1 * 3x + x * 3x)) = 0
(2 + 2x + (3x + 3x2)) = 0

Combine like terms: 2x + 3x = 5x
(2 + 5x + 3x2) = 0

Solving
2 + 5x + 3x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + x)(2 + 3x) = 0

Subproblem 1

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Subproblem 2

Set the factor '(2 + 3x)' equal to zero and attempt to solve: Simplifying 2 + 3x = 0 Solving 2 + 3x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3x = 0 + -2 3x = 0 + -2 Combine like terms: 0 + -2 = -2 3x = -2 Divide each side by '3'. x = -0.6666666667 Simplifying x = -0.6666666667

Solution

x = {-1, -0.6666666667}

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