(3x+2)(x+1)=3x2

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Solution for (3x+2)(x+1)=3x2 equation: 



(3x+2)(x+1)=3x^2

We move all terms to the left:

(3x+2)(x+1)-(3x^2)=0

determiningTheFunctionDomain
-3x^2+(3x+2)(x+1)=0

We multiply parentheses ..

-3x^2+(+3x^2+3x+2x+2)=0

We get rid of parentheses

-3x^2+3x^2+3x+2x+2=0

We add all the numbers together, and all the variables

5x+2=0

We move all terms containing x to the left, all other terms to the right

5x=-2

x=-2/5

x=-2/5

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