(3x+2)(x+2)+(-x-2)3=0

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Solution for (3x+2)(x+2)+(-x-2)3=0 equation:



(3x+2)(x+2)+(-x-2)3=0
We add all the numbers together, and all the variables
(3x+2)(x+2)+(-1x-2)3=0
We multiply parentheses
(3x+2)(x+2)-3x-6=0
We multiply parentheses ..
(+3x^2+6x+2x+4)-3x-6=0
We get rid of parentheses
3x^2+6x+2x-3x+4-6=0
We add all the numbers together, and all the variables
3x^2+5x-2=0
a = 3; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·3·(-2)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*3}=\frac{-12}{6} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*3}=\frac{2}{6} =1/3 $

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