(3x+2)(x+2)=207

Solution for (3x+2)(x+2)=207 equation:

(3x+2)(x+2)=207

We move all terms to the left:

(3x+2)(x+2)-(207)=0

We multiply parentheses ..

(+3x^2+6x+2x+4)-207=0

We get rid of parentheses

3x^2+6x+2x+4-207=0

We add all the numbers together, and all the variables

3x^2+8x-203=0

a = 3; b = 8; c = -203;
Δ = b2-4ac
Δ = 82-4·3·(-203)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-50}{2*3}=\frac{-58}{6}
=-9+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+50}{2*3}=\frac{42}{6}
=7
$