(3x+2)(x+2)=30

Solution for (3x+2)(x+2)=30 equation:

(3x+2)(x+2)=30

We move all terms to the left:

(3x+2)(x+2)-(30)=0

We multiply parentheses ..

(+3x^2+6x+2x+4)-30=0

We get rid of parentheses

3x^2+6x+2x+4-30=0

We add all the numbers together, and all the variables

3x^2+8x-26=0

a = 3; b = 8; c = -26;
Δ = b2-4ac
Δ = 82-4·3·(-26)
Δ = 376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{376}=\sqrt{4*94}=\sqrt{4}*\sqrt{94}=2\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{94}}{2*3}=\frac{-8-2\sqrt{94}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{94}}{2*3}=\frac{-8+2\sqrt{94}}{6}
$