(3x+2)+(3x+2)+(4x)+(4x)=102

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Solution for (3x+2)+(3x+2)+(4x)+(4x)=102 equation:


Simplifying
(3x + 2) + (3x + 2) + (4x) + (4x) = 102

Reorder the terms:
(2 + 3x) + (3x + 2) + (4x) + (4x) = 102

Remove parenthesis around (2 + 3x)
2 + 3x + (3x + 2) + (4x) + (4x) = 102

Reorder the terms:
2 + 3x + (2 + 3x) + (4x) + (4x) = 102

Remove parenthesis around (2 + 3x)
2 + 3x + 2 + 3x + (4x) + (4x) = 102

Reorder the terms:
2 + 2 + 3x + 3x + (4x) + (4x) = 102

Combine like terms: 2 + 2 = 4
4 + 3x + 3x + (4x) + (4x) = 102

Combine like terms: 3x + 3x = 6x
4 + 6x + (4x) + (4x) = 102

Combine like terms: 6x + (4x) = 10x
4 + 10x + (4x) = 102

Combine like terms: 10x + (4x) = 14x
4 + 14x = 102

Solving
4 + 14x = 102

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 14x = 102 + -4

Combine like terms: 4 + -4 = 0
0 + 14x = 102 + -4
14x = 102 + -4

Combine like terms: 102 + -4 = 98
14x = 98

Divide each side by '14'.
x = 7

Simplifying
x = 7

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