(3x+2)+(3x+2)=(4x-2)

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Solution for (3x+2)+(3x+2)=(4x-2) equation: 



(3x+2)+(3x+2)=(4x-2)

We move all terms to the left:

(3x+2)+(3x+2)-((4x-2))=0

We get rid of parentheses

3x+3x-((4x-2))+2+2=0



We calculate terms in parentheses: -((4x-2)), so:

(4x-2)

We get rid of parentheses

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

6x-(4x-2)+4=0

We get rid of parentheses

6x-4x+2+4=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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