(3x+2)+(3x+2)=(4x-2)

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Solution for (3x+2)+(3x+2)=(4x-2) equation:



(3x+2)+(3x+2)=(4x-2)
We move all terms to the left:
(3x+2)+(3x+2)-((4x-2))=0
We get rid of parentheses
3x+3x-((4x-2))+2+2=0
We calculate terms in parentheses: -((4x-2)), so:
(4x-2)
We get rid of parentheses
4x-2
Back to the equation:
-(4x-2)
We add all the numbers together, and all the variables
6x-(4x-2)+4=0
We get rid of parentheses
6x-4x+2+4=0
We add all the numbers together, and all the variables
2x+6=0
We move all terms containing x to the left, all other terms to the right
2x=-6
x=-6/2
x=-3

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