(3x+2)+(4x-3)=17

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Solution for (3x+2)+(4x-3)=17 equation: 



(3x+2)+(4x-3)=17

We move all terms to the left:

(3x+2)+(4x-3)-(17)=0

We get rid of parentheses

3x+4x+2-3-17=0

We add all the numbers together, and all the variables

7x-18=0

We move all terms containing x to the left, all other terms to the right

7x=18

x=18/7

x=2+4/7

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