(3x+2)+(6x-19)+(x+17)=180

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Solution for (3x+2)+(6x-19)+(x+17)=180 equation: 



(3x+2)+(6x-19)+(x+17)=180

We move all terms to the left:

(3x+2)+(6x-19)+(x+17)-(180)=0

We get rid of parentheses

3x+6x+x+2-19+17-180=0

We add all the numbers together, and all the variables

10x-180=0

We move all terms containing x to the left, all other terms to the right

10x=180

x=180/10

x=18

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