(3x+2)+(x+3)+(2x+1)=18

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Solution for (3x+2)+(x+3)+(2x+1)=18 equation: 



(3x+2)+(x+3)+(2x+1)=18

We move all terms to the left:

(3x+2)+(x+3)+(2x+1)-(18)=0

We get rid of parentheses

3x+x+2x+2+3+1-18=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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