(3x+2)+11=(22-x)-11

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Solution for (3x+2)+11=(22-x)-11 equation: 



(3x+2)+11=(22-x)-11

We move all terms to the left:

(3x+2)+11-((22-x)-11)=0

We add all the numbers together, and all the variables

(3x+2)-((-1x+22)-11)+11=0

We get rid of parentheses

3x-((-1x+22)-11)+2+11=0



We calculate terms in parentheses: -((-1x+22)-11), so:

(-1x+22)-11

We get rid of parentheses

-1x+22-11

We add all the numbers together, and all the variables

-1x+11

Back to the equation:

-(-1x+11)



We add all the numbers together, and all the variables

3x-(-1x+11)+13=0

We get rid of parentheses

3x+1x-11+13=0

We add all the numbers together, and all the variables

4x+2=0

We move all terms containing x to the left, all other terms to the right

4x=-2

x=-2/4

x=-1/2

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