(3x+2)+1=(22-x)+5

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Solution for (3x+2)+1=(22-x)+5 equation: 



(3x+2)+1=(22-x)+5

We move all terms to the left:

(3x+2)+1-((22-x)+5)=0

We add all the numbers together, and all the variables

(3x+2)-((-1x+22)+5)+1=0

We get rid of parentheses

3x-((-1x+22)+5)+2+1=0



We calculate terms in parentheses: -((-1x+22)+5), so:

(-1x+22)+5

We get rid of parentheses

-1x+22+5

We add all the numbers together, and all the variables

-1x+27

Back to the equation:

-(-1x+27)



We add all the numbers together, and all the variables

3x-(-1x+27)+3=0

We get rid of parentheses

3x+1x-27+3=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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