(3x+2)+2(2x+3)=3(x+6)+9

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Solution for (3x+2)+2(2x+3)=3(x+6)+9 equation: 



(3x+2)+2(2x+3)=3(x+6)+9

We move all terms to the left:

(3x+2)+2(2x+3)-(3(x+6)+9)=0

We multiply parentheses

(3x+2)+4x-(3(x+6)+9)+6=0

We get rid of parentheses

3x+4x-(3(x+6)+9)+2+6=0



We calculate terms in parentheses: -(3(x+6)+9), so:

3(x+6)+9

We multiply parentheses

3x+18+9

We add all the numbers together, and all the variables

3x+27

Back to the equation:

-(3x+27)



We add all the numbers together, and all the variables

7x-(3x+27)+8=0

We get rid of parentheses

7x-3x-27+8=0

We add all the numbers together, and all the variables

4x-19=0

We move all terms containing x to the left, all other terms to the right

4x=19

x=19/4

x=4+3/4

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