(3x+2)+22=(4x-6)

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Solution for (3x+2)+22=(4x-6) equation: 



(3x+2)+22=(4x-6)

We move all terms to the left:

(3x+2)+22-((4x-6))=0

We get rid of parentheses

3x-((4x-6))+2+22=0



We calculate terms in parentheses: -((4x-6)), so:

(4x-6)

We get rid of parentheses

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

3x-(4x-6)+24=0

We get rid of parentheses

3x-4x+6+24=0

We add all the numbers together, and all the variables

-1x+30=0

We move all terms containing x to the left, all other terms to the right

-x=-30

x=-30/-1

x=+30

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