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(3x+2)-(x+2)=(4x+5)-(3x+2)
We move all terms to the left:
(3x+2)-(x+2)-((4x+5)-(3x+2))=0
We get rid of parentheses
3x-x-((4x+5)-(3x+2))+2-2=0
We calculate terms in parentheses: -((4x+5)-(3x+2)), so:We add all the numbers together, and all the variables
(4x+5)-(3x+2)
We get rid of parentheses
4x-3x+5-2
We add all the numbers together, and all the variables
x+3
Back to the equation:
-(x+3)
2x-(x+3)=0
We get rid of parentheses
2x-x-3=0
We add all the numbers together, and all the variables
x-3=0
We move all terms containing x to the left, all other terms to the right
x=3
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