(3x+2)-(x-1)=-(2x-2)-(2x+4)

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Solution for (3x+2)-(x-1)=-(2x-2)-(2x+4) equation:



(3x+2)-(x-1)=-(2x-2)-(2x+4)
We move all terms to the left:
(3x+2)-(x-1)-(-(2x-2)-(2x+4))=0
We get rid of parentheses
3x-x-(-(2x-2)-(2x+4))+2+1=0
We calculate terms in parentheses: -(-(2x-2)-(2x+4)), so:
-(2x-2)-(2x+4)
We get rid of parentheses
-2x-2x+2-4
We add all the numbers together, and all the variables
-4x-2
Back to the equation:
-(-4x-2)
We add all the numbers together, and all the variables
2x-(-4x-2)+3=0
We get rid of parentheses
2x+4x+2+3=0
We add all the numbers together, and all the variables
6x+5=0
We move all terms containing x to the left, all other terms to the right
6x=-5
x=-5/6
x=-5/6

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