(3x+2)-7=2(x+5)

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Solution for (3x+2)-7=2(x+5) equation: 



(3x+2)-7=2(x+5)

We move all terms to the left:

(3x+2)-7-(2(x+5))=0

We get rid of parentheses

3x-(2(x+5))+2-7=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

3x-(2x+10)-5=0

We get rid of parentheses

3x-2x-10-5=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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