(3x+2)/(2x+3)=8

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Solution for (3x+2)/(2x+3)=8 equation: 



(3x+2)/(2x+3)=8

We move all terms to the left:

(3x+2)/(2x+3)-(8)=0



Domain of the equation: (2x+3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-3

x!=-3/2

x!=-1+1/2

x∈R



We multiply all the terms by the denominator


(3x+2)-8*(2x+3)=0

We multiply parentheses

(3x+2)-16x-24=0

We get rid of parentheses

3x-16x+2-24=0

We add all the numbers together, and all the variables

-13x-22=0

We move all terms containing x to the left, all other terms to the right

-13x=22

x=22/-13

x=-1+9/13

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