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(3x+2)/(x-4)=-5
We move all terms to the left:
(3x+2)/(x-4)-(-5)=0
Domain of the equation: (x-4)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=4
x∈R
(3x+2)/(x-4)+5=0
We multiply all the terms by the denominator
(3x+2)+5*(x-4)=0
We multiply parentheses
(3x+2)+5x-20=0
We get rid of parentheses
3x+5x+2-20=0
We add all the numbers together, and all the variables
8x-18=0
We move all terms containing x to the left, all other terms to the right
8x=18
x=18/8
x=2+1/4
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