(3x+2)/(x-4)=5

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Solution for (3x+2)/(x-4)=5 equation: 



(3x+2)/(x-4)=5

We move all terms to the left:

(3x+2)/(x-4)-(5)=0



Domain of the equation: (x-4)!=0

We move all terms containing x to the left, all other terms to the right

x!=4

x∈R



We multiply all the terms by the denominator


(3x+2)-5*(x-4)=0

We multiply parentheses

(3x+2)-5x+20=0

We get rid of parentheses

3x-5x+2+20=0

We add all the numbers together, and all the variables

-2x+22=0

We move all terms containing x to the left, all other terms to the right

-2x=-22

x=-22/-2

x=+11

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