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(3x+2)/(x-5)=8
We move all terms to the left:
(3x+2)/(x-5)-(8)=0
Domain of the equation: (x-5)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=5
x∈R
(3x+2)-8*(x-5)=0
We multiply parentheses
(3x+2)-8x+40=0
We get rid of parentheses
3x-8x+2+40=0
We add all the numbers together, and all the variables
-5x+42=0
We move all terms containing x to the left, all other terms to the right
-5x=-42
x=-42/-5
x=8+2/5
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