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(3x+2)/2-(3x+1)/6=5/3+2x
We move all terms to the left:
(3x+2)/2-(3x+1)/6-(5/3+2x)=0
Domain of the equation: 3+2x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x)!=-3
x!=-3/1
x!=-3
x∈R
(3x+2)/2-(3x+1)/6-(+2x+5/3)=0
We get rid of parentheses
(3x+2)/2-(3x+1)/6-2x-5/3=0
We calculate fractions
There is no solution for this equation
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