(3x+2)/2=(5x-5)/3

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Solution for (3x+2)/2=(5x-5)/3 equation: 



(3x+2)/2=(5x-5)/3

We move all terms to the left:

(3x+2)/2-((5x-5)/3)=0

We calculate fractions


3x/()+(-((5x-5)*2)/()=0



We calculate terms in parentheses: +(-((5x-5)*2)/(), so:

-((5x-5)*2)/(

We multiply all the terms by the denominator


-((5x-5)*2)



We calculate terms in parentheses: -((5x-5)*2), so:

(5x-5)*2

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)



We get rid of parentheses

-10x+10

Back to the equation:

+(-10x+10)



We get rid of parentheses

3x/()-10x+10=0

We multiply all the terms by the denominator


3x-10x*()+10*()=0

We add all the numbers together, and all the variables

3x-10x*()=0

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