(3x+2)/3=(x+9)/6

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Solution for (3x+2)/3=(x+9)/6 equation: 



(3x+2)/3=(x+9)/6

We move all terms to the left:

(3x+2)/3-((x+9)/6)=0

We calculate fractions


3x/()+(-((x+9)*3)/()=0



We calculate terms in parentheses: +(-((x+9)*3)/(), so:

-((x+9)*3)/(

We multiply all the terms by the denominator


-((x+9)*3)



We calculate terms in parentheses: -((x+9)*3), so:

(x+9)*3

We multiply parentheses

3x+27

Back to the equation:

-(3x+27)



We get rid of parentheses

-3x-27

Back to the equation:

+(-3x-27)



We get rid of parentheses

3x/()-3x-27=0

We multiply all the terms by the denominator


3x-3x*()-27*()=0

We add all the numbers together, and all the variables

3x-3x*()=0

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