(3x+2)/3=(x-7)/(2x+1)

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Solution for (3x+2)/3=(x-7)/(2x+1) equation: 


D( x )

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

x in (-oo:-1/2) U (-1/2:+oo)

(3*x+2)/3 = (x-7)/(2*x+1) // - (x-7)/(2*x+1)

(3*x+2)/3-((x-7)/(2*x+1)) = 0

(3*x+2)/3+(-1*(x-7))/(2*x+1) = 0

((3*x+2)*(2*x+1))/(3*(2*x+1))+(-1*3*(x-7))/(3*(2*x+1)) = 0

(3*x+2)*(2*x+1)-1*3*(x-7) = 0

6*x^2+4*x+23 = 0

6*x^2+4*x+23 = 0

6*x^2+4*x+23 = 0

DELTA = 4^2-(4*6*23)

DELTA = -536

DELTA < 0

1 = 0

1/(3*(2*x+1)) = 0

1/(3*(2*x+1)) = 0 // * 3*(2*x+1)

1 = 0

x belongs to the empty set

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