(3x+2)/5=(4x-7)/6

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Solution for (3x+2)/5=(4x-7)/6 equation: 



(3x+2)/5=(4x-7)/6

We move all terms to the left:

(3x+2)/5-((4x-7)/6)=0

We calculate fractions


3x/()+(-((4x-7)*5)/()=0



We calculate terms in parentheses: +(-((4x-7)*5)/(), so:

-((4x-7)*5)/(

We multiply all the terms by the denominator


-((4x-7)*5)



We calculate terms in parentheses: -((4x-7)*5), so:

(4x-7)*5

We multiply parentheses

20x-35

Back to the equation:

-(20x-35)



We get rid of parentheses

-20x+35

Back to the equation:

+(-20x+35)



We get rid of parentheses

3x/()-20x+35=0

We multiply all the terms by the denominator


3x-20x*()+35*()=0

We add all the numbers together, and all the variables

3x-20x*()=0

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