(3x+2)/7-(x+4)/5=2

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Solution for (3x+2)/7-(x+4)/5=2 equation:


(3x+2)/7-(x+4)/5=2

We simplify the equation to the form, which is simple to understand
(3x+2)/7-(x+4)/5=2

Reorder the terms in parentheses
( + 0.428571428571x + 0.285714285714)-(x+4)/5=2

Remove unnecessary parentheses
+ 0.428571428571x + 0.285714285714-(x+4)/5=2

Reorder the terms in parentheses
+ 0.428571428571x + 0.285714285714-( + 0.2x + 0.8)=2

Remove unnecessary parentheses
+ 0.428571428571x + 0.285714285714-0.2x-0.8=2

We move all terms containing x to the left and all other terms to the right.
+ 0.428571428571x-0.2x=+2-0.285714285714 + 0.8

We simplify left and right side of the equation.
+ 0.228571428571x=+2.51428571429

We divide both sides of the equation by 0.228571428571 to get x.
x=11

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