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(3x+2)/7=(2x+16)/14
We move all terms to the left:
(3x+2)/7-((2x+16)/14)=0
We calculate fractions
3x/()+(-((2x+16)*7)/()=0
We calculate terms in parentheses: +(-((2x+16)*7)/(), so:We get rid of parentheses
-((2x+16)*7)/(
We multiply all the terms by the denominator
-((2x+16)*7)
We calculate terms in parentheses: -((2x+16)*7), so:We get rid of parentheses
(2x+16)*7
We multiply parentheses
14x+112
Back to the equation:
-(14x+112)
-14x-112
Back to the equation:
+(-14x-112)
3x/()-14x-112=0
We multiply all the terms by the denominator
3x-14x*()-112*()=0
We add all the numbers together, and all the variables
3x-14x*()=0
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