(3x+2)/7=(2x+16)/14

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Solution for (3x+2)/7=(2x+16)/14 equation: 



(3x+2)/7=(2x+16)/14

We move all terms to the left:

(3x+2)/7-((2x+16)/14)=0

We calculate fractions


3x/()+(-((2x+16)*7)/()=0



We calculate terms in parentheses: +(-((2x+16)*7)/(), so:

-((2x+16)*7)/(

We multiply all the terms by the denominator


-((2x+16)*7)



We calculate terms in parentheses: -((2x+16)*7), so:

(2x+16)*7

We multiply parentheses

14x+112

Back to the equation:

-(14x+112)



We get rid of parentheses

-14x-112

Back to the equation:

+(-14x-112)



We get rid of parentheses

3x/()-14x-112=0

We multiply all the terms by the denominator


3x-14x*()-112*()=0

We add all the numbers together, and all the variables

3x-14x*()=0

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