(3x+2)/7=(4x-1)/5

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Solution for (3x+2)/7=(4x-1)/5 equation: 



(3x+2)/7=(4x-1)/5

We move all terms to the left:

(3x+2)/7-((4x-1)/5)=0

We calculate fractions


3x/()+(-((4x-1)*7)/()=0



We calculate terms in parentheses: +(-((4x-1)*7)/(), so:

-((4x-1)*7)/(

We multiply all the terms by the denominator


-((4x-1)*7)



We calculate terms in parentheses: -((4x-1)*7), so:

(4x-1)*7

We multiply parentheses

28x-7

Back to the equation:

-(28x-7)



We get rid of parentheses

-28x+7

Back to the equation:

+(-28x+7)



We get rid of parentheses

3x/()-28x+7=0

We multiply all the terms by the denominator


3x-28x*()+7*()=0

We add all the numbers together, and all the variables

3x-28x*()=0

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