(3x+2)2=3x2+6x+4

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Solution for (3x+2)2=3x2+6x+4 equation: 



(3x+2)2=3x^2+6x+4

We move all terms to the left:

(3x+2)2-(3x^2+6x+4)=0

We multiply parentheses

6x-(3x^2+6x+4)+4=0

We get rid of parentheses

-3x^2+6x-6x-4+4=0

We add all the numbers together, and all the variables

-3x^2=0

a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-6}=0$

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