(3x+2)=(9x-77)

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Solution for (3x+2)=(9x-77) equation: 



(3x+2)=(9x-77)

We move all terms to the left:

(3x+2)-((9x-77))=0

We get rid of parentheses

3x-((9x-77))+2=0



We calculate terms in parentheses: -((9x-77)), so:

(9x-77)

We get rid of parentheses

9x-77

Back to the equation:

-(9x-77)



We get rid of parentheses

3x-9x+77+2=0

We add all the numbers together, and all the variables

-6x+79=0

We move all terms containing x to the left, all other terms to the right

-6x=-79

x=-79/-6

x=13+1/6

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