(3x+2)x=104

Solution for (3x+2)x=104 equation:

(3x+2)x=104

We move all terms to the left:

(3x+2)x-(104)=0

We multiply parentheses

3x^2+2x-104=0

a = 3; b = 2; c = -104;
Δ = b2-4ac
Δ = 22-4·3·(-104)
Δ = 1252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1252}=\sqrt{4*313}=\sqrt{4}*\sqrt{313}=2\sqrt{313}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{313}}{2*3}=\frac{-2-2\sqrt{313}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{313}}{2*3}=\frac{-2+2\sqrt{313}}{6}
$