(3x+2.5)(4x+3.75)=26.25

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Solution for (3x+2.5)(4x+3.75)=26.25 equation:



(3x+2.5)(4x+3.75)=26.25
We move all terms to the left:
(3x+2.5)(4x+3.75)-(26.25)=0
We add all the numbers together, and all the variables
(3x+2.5)(4x+3.75)-26.25=0
We multiply parentheses ..
(+12x^2+11.25x+10x+9.375)-26.25=0
We get rid of parentheses
12x^2+11.25x+10x+9.375-26.25=0
We add all the numbers together, and all the variables
12x^2+21.25x-16.875=0
a = 12; b = 21.25; c = -16.875;
Δ = b2-4ac
Δ = 21.252-4·12·(-16.875)
Δ = 1261.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21.25)-\sqrt{1261.5625}}{2*12}=\frac{-21.25-\sqrt{1261.5625}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21.25)+\sqrt{1261.5625}}{2*12}=\frac{-21.25+\sqrt{1261.5625}}{24} $

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