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(3x+20)(6x+12)=180
We move all terms to the left:
(3x+20)(6x+12)-(180)=0
We multiply parentheses ..
(+18x^2+36x+120x+240)-180=0
We get rid of parentheses
18x^2+36x+120x+240-180=0
We add all the numbers together, and all the variables
18x^2+156x+60=0
a = 18; b = 156; c = +60;
Δ = b2-4ac
Δ = 1562-4·18·60
Δ = 20016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20016}=\sqrt{144*139}=\sqrt{144}*\sqrt{139}=12\sqrt{139}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(156)-12\sqrt{139}}{2*18}=\frac{-156-12\sqrt{139}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(156)+12\sqrt{139}}{2*18}=\frac{-156+12\sqrt{139}}{36} $
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