(3x+20)+(3x+20)=(6x-16)

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Solution for (3x+20)+(3x+20)=(6x-16) equation: 



(3x+20)+(3x+20)=(6x-16)

We move all terms to the left:

(3x+20)+(3x+20)-((6x-16))=0

We get rid of parentheses

3x+3x-((6x-16))+20+20=0



We calculate terms in parentheses: -((6x-16)), so:

(6x-16)

We get rid of parentheses

6x-16

Back to the equation:

-(6x-16)



We add all the numbers together, and all the variables

6x-(6x-16)+40=0

We get rid of parentheses

6x-6x+16+40=0

We add all the numbers together, and all the variables

56!=0

There is no solution for this equation

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