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(3x+20)=(x+6)
We move all terms to the left:
(3x+20)-((x+6))=0
We get rid of parentheses
3x-((x+6))+20=0
We calculate terms in parentheses: -((x+6)), so:We get rid of parentheses
(x+6)
We get rid of parentheses
x+6
Back to the equation:
-(x+6)
3x-x-6+20=0
We add all the numbers together, and all the variables
2x+14=0
We move all terms containing x to the left, all other terms to the right
2x=-14
x=-14/2
x=-7
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