(3x+20+(7x+12))/3=24

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Solution for (3x+20+(7x+12))/3=24 equation: 



(3x+20+(7x+12))/3=24

We move all terms to the left:

(3x+20+(7x+12))/3-(24)=0

We multiply all the terms by the denominator


(3x+20+(7x+12))-24*3=0



We calculate terms in parentheses: +(3x+20+(7x+12)), so:

3x+20+(7x+12)

determiningTheFunctionDomain
3x+(7x+12)+20

We get rid of parentheses

3x+7x+12+20

We add all the numbers together, and all the variables

10x+32

Back to the equation:

+(10x+32)



We add all the numbers together, and all the variables

(10x+32)-72=0

We get rid of parentheses

10x+32-72=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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