(3x+20/5)+(x+25/6)=12

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Solution for (3x+20/5)+(x+25/6)=12 equation:



(3x+20/5)+(x+25/6)=12
We move all terms to the left:
(3x+20/5)+(x+25/6)-(12)=0
We add all the numbers together, and all the variables
(3x+4)+(+x+25/6)-12=0
We get rid of parentheses
3x+x+4-12+25/6=0
We multiply all the terms by the denominator
3x*6+x*6+25+4*6-12*6=0
We add all the numbers together, and all the variables
3x*6+x*6-23=0
Wy multiply elements
18x+6x-23=0
We add all the numbers together, and all the variables
24x-23=0
We move all terms containing x to the left, all other terms to the right
24x=23
x=23/24
x=23/24

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