(3x+21)(2x-8)=-144

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Solution for (3x+21)(2x-8)=-144 equation:



(3x+21)(2x-8)=-144
We move all terms to the left:
(3x+21)(2x-8)-(-144)=0
We add all the numbers together, and all the variables
(3x+21)(2x-8)+144=0
We multiply parentheses ..
(+6x^2-24x+42x-168)+144=0
We get rid of parentheses
6x^2-24x+42x-168+144=0
We add all the numbers together, and all the variables
6x^2+18x-24=0
a = 6; b = 18; c = -24;
Δ = b2-4ac
Δ = 182-4·6·(-24)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*6}=\frac{-48}{12} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*6}=\frac{12}{12} =1 $

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