(3x+21)+(2x-6)=50

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Solution for (3x+21)+(2x-6)=50 equation: 



(3x+21)+(2x-6)=50

We move all terms to the left:

(3x+21)+(2x-6)-(50)=0

We get rid of parentheses

3x+2x+21-6-50=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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