(3x+21/6)+(x+21/5)=14

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Solution for (3x+21/6)+(x+21/5)=14 equation: 



(3x+21/6)+(x+21/5)=14

We move all terms to the left:

(3x+21/6)+(x+21/5)-(14)=0

We add all the numbers together, and all the variables

(+3x+21/6)+(+x+21/5)-14=0

We get rid of parentheses

3x+x-14+21/6+21/5=0

We calculate fractions

There is no solution for this equation

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