(3x+21/6)+(x+21/5)=14

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Solution for (3x+21/6)+(x+21/5)=14 equation:



(3x+21/6)+(x+21/5)=14
We move all terms to the left:
(3x+21/6)+(x+21/5)-(14)=0
We add all the numbers together, and all the variables
(+3x+21/6)+(+x+21/5)-14=0
We get rid of parentheses
3x+x-14+21/6+21/5=0
We calculate fractions
There is no solution for this equation

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