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(3x+25)(5x+5)=x
We move all terms to the left:
(3x+25)(5x+5)-(x)=0
We add all the numbers together, and all the variables
-1x+(3x+25)(5x+5)=0
We multiply parentheses ..
(+15x^2+15x+125x+125)-1x=0
We get rid of parentheses
15x^2+15x+125x-1x+125=0
We add all the numbers together, and all the variables
15x^2+139x+125=0
a = 15; b = 139; c = +125;
Δ = b2-4ac
Δ = 1392-4·15·125
Δ = 11821
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(139)-\sqrt{11821}}{2*15}=\frac{-139-\sqrt{11821}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(139)+\sqrt{11821}}{2*15}=\frac{-139+\sqrt{11821}}{30} $
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