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(3x+26=6x-13.x)
We move all terms to the left:
(3x+26-(6x-13.x))=0
We add all the numbers together, and all the variables
(3x+26-(-7x))=0
We calculate terms in parentheses: +(3x+26-(-7x)), so:We get rid of parentheses
3x+26-(-7x)
determiningTheFunctionDomain 3x-(-7x)+26
We get rid of parentheses
3x+7x+26
We add all the numbers together, and all the variables
10x+26
Back to the equation:
+(10x+26)
10x+26=0
We move all terms containing x to the left, all other terms to the right
10x=-26
x=-26/10
x=-2+3/5
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