(3x+28)+(4x-23)=180

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Solution for (3x+28)+(4x-23)=180 equation:



(3x+28)+(4x-23)=180
We move all terms to the left:
(3x+28)+(4x-23)-(180)=0
We get rid of parentheses
3x+4x+28-23-180=0
We add all the numbers together, and all the variables
7x-175=0
We move all terms containing x to the left, all other terms to the right
7x=175
x=175/7
x=25

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